A good answer might be:

No — array indexes start at zero, and go up to length-1.

IndexOutOfBoundsException

Here is a program that asks the user for an integer and for an array index where it is to be placed. Only indexes 0 through 9 are allowed. Any other index causes an IndexOutOfBoundsException.

import java.lang.* ;
import java.io.* ;

public class IndexPractice
{
  public static void main ( String[] a ) throws IOException
  {
    BufferedReader stdin = 
        new BufferedReader ( new InputStreamReader( System.in ) );
    String inData; int data=0, slot=0 ;

    int[] value = new int[10];

    try
    {
      System.out.println("Enter the data:");
      inData = stdin.readLine();
      data   = Integer.parseInt( inData );
      System.out.println("Enter the array index:");
      inData = stdin.readLine();
      slot   = Integer.parseInt( inData );

      value[slot] = data;
    }

    catch (NumberFormatException ex )
    {
      System.out.println("This is your problem: " + ex.getMessage() 
          + "\nHere is where it happened:\n");
      ex.printStackTrace();
    }

    catch (IndexOutOfBoundsException ex )
    {
      System.out.println("This is your problem: " + ex.getMessage() 
          + "\nHere is where it happened:\n");
      ex.printStackTrace();
    }

    System.out.println("Good-by" );
  }
}

 

QUESTION 3:

If the user enters:

8
10
will an exception be thrown?